|
|
Torque Conversion
Chart
| |
lb-ft |
lb-in |
oz-in |
Dyne-cm |
Nm |
Ncm |
Kpm(kgfm) |
g cm |
| lb-ft |
1 |
12 |
192 |
1.356x107 |
1.356 |
1.356x102 |
0.1383 |
1.383x104 |
| lb-in |
8.333x10-2 |
1 |
16 |
1.1298x106 |
0.113 |
11.3 |
1.1152x10-2 |
1.152x103 |
| oz-in |
5.208x10-3 |
6.250x10-2 |
1 |
7.062x104 |
7.062x10-3 |
0.7062 |
7.201x10-4 |
72.01 |
| Dyne-cm |
7.376x10-3 |
8.851x10-7 |
1.416x10-5 |
1 |
10-7 |
10-5 |
1.0197x10-8 |
1.0197x10-3 |
| Nm |
0.7376 |
8.8509 |
1.4161x102 |
107 |
1 |
102 |
0.10197 |
1.0197x104 |
| Ncm |
7.376x10-3 |
8.8509x10-2 |
1.4161 |
105 |
10-2 |
1 |
1.0197x10-3 |
0.10197 |
| Kpm(kgfm) |
7.233 |
86.796 |
1.389x103 |
9.8067x107 |
9.8066 |
980.665 |
1 |
105 |
| g cm |
7.233x10-5 |
8.680x10-4 |
1.389x10-2 |
980.67 |
9.8066x10-5 |
9.8066x10-3 |
10-5 |
1 |
| Temperature
Conversion Formula |
| Farenheit =
9/5ºC + 32 |
| Centigrade
= 5/9 (ºF - 32) |
|
Horsepower
Horsepower is
a common unit for measuring the rate of doing work. When James
Watt perfected the steam engine, he wished to compare its
performance with that of a horse. It was estimated that a
horse could raise a bail of cotton weighing 550 pounds vertically
at a rate of one foot in one second. Therefore, the unit of
horsepower was established at 550 ft-lbs. / sec. or 33,000
ft-lbs. / min.
In our industry we need to express horsepower in terms of
rotory motion.
 |
Circumference = 2 R |
Therefore, the work accomplished
can be expressed as follows:
| HP = |
Force
(F) (lbs) X Radius (R) X 2 X RPM |
| |
 |
| |
33,000
X 12 (in-lbs/min) |
| |
|
| |
(F X
R = T) |
| |
|
| |
|
Therefore:
| HP = |
| Torque (T)
(in-lbs) X RPM |
 |
| 63,025 |
|
| |
|
| or: |
| T (in-lbs)
= |
| HP x
63,025 |
 |
| RPM |
|
|
|